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The original assumption was that the interrupt numbers are divided so that 16 pins from 1 port are handled by a single interrupt source. So source 0 would handle pins 0-15 and source 1 would handle pins 16-31. This assumption is wrong, each pin has two sources, thus there are two interrupt lines for each pin. The driver uses source 0, and leaves source 1 disabled. |
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| a64 | ||
| fvp-v8r | ||
| goldfish | ||
| imx8 | ||
| imx9 | ||
| qemu | ||
| rk3399 | ||
| .gitignore | ||
| arch.h | ||
| elf.h | ||
| inttypes.h | ||
| irq.h | ||
| limits.h | ||
| setjmp.h | ||
| spinlock.h | ||
| stdarg.h | ||
| syscall.h | ||
| types.h | ||